Strona 1 z 1
oblicz calke
: 13 gru 2008, o 00:35
autor: gufox
\(\displaystyle{ \int sinxsin \frac{x}{2}sin \frac{x}{3}dx}\)
oblicz calke
: 13 gru 2008, o 00:57
autor: soku11
\(\displaystyle{ \sin (x)\cdot \sin ft(\frac{x}{2}\right)\cdot\sin\left(\frac{x}{3}\right)=
\frac{1}{2}\sin (x)\left[ \cos ft(\frac{5}{6}x\right)-\cos ft(\frac{x}{6}\right)\right]=
\frac{1}{2}\sin (x)\cos ft(\frac{5}{6}x\right)-\frac{1}{2}\sin (x)\cos ft(\frac{x}{6}\right)=
\frac{1}{4}\sin ft(\frac{11}{6}x\right)+
\frac{1}{4}\sin ft(\frac{x}{6}\right)-
\frac{1}{4}\sin ft(\frac{7}{6}x\right)-
\frac{1}{4}\sin ft(\frac{x}{6}\right)=
\frac{1}{4}\left[ \sin ft(\frac{11}{6}x\right)-\sin\left(\frac{7}{6}x\right) \right]}\)
Pozdrawiam
oblicz calke
: 13 gru 2008, o 09:48
autor: gufox
takie rzeczy sie liczy z prostego wzoru. dzieki