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\(\displaystyle{ \lim_{x\to \ 0 }\frac{x^3}{\sin2x}}\)

\(\displaystyle{ \lim_{x\to \ 0 }\frac{x^3}{\sin2x}=H=
\lim_{x\to \ 0 }\frac{3x^2}{2\cos2x}=\frac{3}{2}\lim_{x\to\ 0} \frac{x^2}{cos2x}=
\frac{3}{2} ft [\frac{0}{1}\right]=0}\)

POZDRO

Albo:
\(\displaystyle{ \lim_{x\to 0}\frac{x^{3}}{\sin 2x} = \lim_{x\to 0}\left(\frac{x^{2}}{2\cos x}\cdot \frac{x}{\sin x}\right) = 0\cdot 1 = 0}\)

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