pochodne cząstkowe f'xy (z pierwiastkiem)
: 3 wrz 2010, o 11:52
oblicz \(\displaystyle{ f'xy}\)
\(\displaystyle{ f(x,y)= \sqrt{x^2+2y}}\)
\(\displaystyle{ f'x= \frac{1}{2 \sqrt{x^2+2y} } \cdot 2x}\)
\(\displaystyle{ f'xy=[ \frac{ 2( \frac{1}{2 \sqrt{x^2+2y} } \cdot 2 )}{(2 \sqrt{x^2+2y} )^2} ] \cdot 2x}\)
\(\displaystyle{ f(x,y)= \sqrt{x^2+2y}}\)
\(\displaystyle{ f'x= \frac{1}{2 \sqrt{x^2+2y} } \cdot 2x}\)
\(\displaystyle{ f'xy=[ \frac{ 2( \frac{1}{2 \sqrt{x^2+2y} } \cdot 2 )}{(2 \sqrt{x^2+2y} )^2} ] \cdot 2x}\)