równanie
: 18 mar 2008, o 19:59
Rozwiąż równanie
\(\displaystyle{ 3x ^{3}+ x ^{2} + 4x -4=0}\)
\(\displaystyle{ 3x ^{3}+ x ^{2} + 4x -4=0}\)
\(\displaystyle{ 3x^{3}+x^{2}+4x-4=0}\)
\(\displaystyle{ W(\frac{2}{3})=0}\)
\(\displaystyle{ 3x^{3}-2x^{2}+3x^{2}-2x+6x-4=0}\)
\(\displaystyle{ (x-\frac{2}{3})(3x^{2}+3x+6)=0}\)
\(\displaystyle{ (x-\frac{2}{3})(x^{2}+x+2)=0}\)
\(\displaystyle{ x=\frac{2}{3}}\) ,a w drugim nawiasie już nie daje pierwiastków bo \(\displaystyle{ \Delta}\)