Wielomian stopnia czwartego-rozwiąż
: 5 mar 2008, o 13:08
\(\displaystyle{ 16x^{4}+16x^{3}-4x^{2}-4x+1=0}\)
\(\displaystyle{ 16(x^{4}+x^{3}-\frac{1}{4}x^{2}-\frac{1}{4}x+\frac{1}{16})=}\)
\(\displaystyle{ =16(x^{2}+\frac{1}{2}x-\frac{1}{4})^{2}=16(x-\frac{-1-\sqrt{5}}{4})^{2} \ (x-\frac{-1+\sqrt{5}}{4})^{2}}\)