prosta zależność
: 18 sty 2012, o 19:46
Proszę o sprawdzenie:
\(\displaystyle{ \cos 2t \cdot 2 \cos 2t + 2\sin 2t \cdot \sin 2t= 2\cos ^{2}4t+2\sin ^{2}4t= 2(\cos ^{2}4t+\sin ^{2}4t)=2 \cdot 1=2}\)
\(\displaystyle{ \cos 2t \cdot 2 \cos 2t + 2\sin 2t \cdot \sin 2t= 2\cos ^{2}4t+2\sin ^{2}4t= 2(\cos ^{2}4t+\sin ^{2}4t)=2 \cdot 1=2}\)