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Obliczanie wielomianów

: 23 lis 2010, o 20:42
autor: Orszulla
sprawdzenie zadań
W(x)=\(\displaystyle{ x^3-3x^2+5x-1
W(\(\displaystyle{ - \sqrt{2})=(- \sqrt{2})^3-3( -\sqrt{2} )^2+5(- \sqrt{2})-1=-2 \sqrt{2}+6+5(- \sqrt{2})-1=-2 \sqrt{2}+10(- \sqrt{2})=8}\)

W(-1)=\(\displaystyle{ (-1)^3-3(-1)^2+5(-1)-1= -1-3+5(-1)-1=-4-5-1=-10}\)

\(\displaystyle{ W(\frac{1}{ \sqrt{3}})=(\frac{1}{ \sqrt{3}})^3-3(\frac{1}{ \sqrt{3}})^2+5(\frac{1}{ \sqrt{3}})-1=\frac{1}{ 3\sqrt{3}}-1+5 \cdot \frac{1}{ \sqrt{3}}-1=\frac{1}{ 3\sqrt{3}}-1+5 \cdot \frac{1}{ \sqrt{3}}-1=\frac{1}{3 \sqrt{3}}+3 \cdot \frac{1}{ \sqrt{3}}}\)}\)

Obliczanie wielomianów

: 23 lis 2010, o 20:51
autor: anna_
1. źle
2. dobrze
3. źle