Podać uzasadnienie kombinatoryczne...
: 18 paź 2010, o 17:37
a) \(\displaystyle{ {n \choose k} = {n \choose n-k}}\)
b) \(\displaystyle{ {n \choose 0} + {n \choose 1} + {n \choose 2} +...+ {n \choose n} = 2^{n}}\)
c) \(\displaystyle{ {n \choose k} = {n-1 \choose k} + {n-1 \choose k-1}}\)
Z góry dzięki;]
b) \(\displaystyle{ {n \choose 0} + {n \choose 1} + {n \choose 2} +...+ {n \choose n} = 2^{n}}\)
c) \(\displaystyle{ {n \choose k} = {n-1 \choose k} + {n-1 \choose k-1}}\)
Z góry dzięki;]