wykazac nierownosc
: 1 maja 2010, o 16:47
Wykaz, ze jezeli
\(\displaystyle{ A,B \subset \Omega}\)
\(\displaystyle{ P(A)= \frac{1}{4}}\)
\(\displaystyle{ P(B)= \frac{1}{3}}\)
to:
\(\displaystyle{ \frac{1}{3} \le P(A \cup B) \le \frac{7}{12}}\)
\(\displaystyle{ P(B-A) \ge \frac{1}{12}}\)
\(\displaystyle{ A,B \subset \Omega}\)
\(\displaystyle{ P(A)= \frac{1}{4}}\)
\(\displaystyle{ P(B)= \frac{1}{3}}\)
to:
\(\displaystyle{ \frac{1}{3} \le P(A \cup B) \le \frac{7}{12}}\)
\(\displaystyle{ P(B-A) \ge \frac{1}{12}}\)