rozwiaz rownosc
: 10 mar 2010, o 17:47
\(\displaystyle{ x^{3}+5x^{2} - x - 5 = 0}\)
\(\displaystyle{ x^{3}+5x^{2}-x-5=0}\)
\(\displaystyle{ x(x^{2}-1)+5(x^{2}-1)=0}\)
\(\displaystyle{ (x+5)(x^{2}-1)=0}\)
\(\displaystyle{ (x+5)(x-1)(x+1)=0}\)
\(\displaystyle{ x=-5 \vee x=-1 \vee x=1}\)