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: 13 lip 2006, o 17:13
\(\displaystyle{ z^{4}-2z^{2}+4 = 0}\)
no więc wyszło mi:
\(\displaystyle{ z_{0}=\frac{\sqrt{6}}{2}-\frac{\sqrt{2}}{2}i}\)
\(\displaystyle{ z_{1}=-\frac{\sqrt{6}}{2}+\frac{\sqrt{2}}{2}i}\)
\(\displaystyle{ z_{2}=\frac{\sqrt{6}}{2}+\frac{\sqrt{2}}{2}i}\)
\(\displaystyle{ z_{3}=-\frac{\sqrt{6}}{2}-\frac{\sqrt{2}}{2}i}\)