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potegi, ulamki

: 11 lis 2009, o 21:18
autor: Andziunia06
(-2) \(\displaystyle{ ^{-3}}\) =

(-5)\(\displaystyle{ ^{3}}\) =

(-0,0789) \(\displaystyle{ ^{0}}\) =

(1238) \(\displaystyle{ ^{1}}\) =

-(-\(\displaystyle{ \frac{2}{3}}\) ) \(\displaystyle{ ^{-3}}\) =

\(\displaystyle{ \sqrt{6}}\)\(\displaystyle{ \frac{1}{4}}\) =

\(\displaystyle{ \sqrt{5}}\)\(\displaystyle{ \frac{4}{9}}\) =

\(\displaystyle{ \sqrt[3]{-0,008}}\) =

potegi, ulamki

: 11 lis 2009, o 21:42
autor: barakuda
\(\displaystyle{ (-2) ^{-3} = (-\frac{1}{2} )^{3} = - \frac{1}{8}}\)

\(\displaystyle{ (-5)^{3} =-125}\)

\(\displaystyle{ (-0,0789) ^{0} =1}\)

\(\displaystyle{ (1238 ) ^{1} = 1238}\)

\(\displaystyle{ -(-\frac{2}{3} ) ^{-3} =- \left( - \frac{3}{2} \right) ^3 = \frac{27}{8}}\)

\(\displaystyle{ \sqrt[3]{-0,008}=-0,2}\)

potegi, ulamki

: 11 lis 2009, o 21:45
autor: Nixur
1/8; -125; 1;1238;27/8;+-1/2; tożsame z sobą; -0,2