obicz równania
: 24 paź 2009, o 14:11
\(\displaystyle{ a)}\) \(\displaystyle{ \left(2x + 1 \right) ^{2} + \left(5 - x \right) ^{2} = 5 \left(x ^{2} + 1 \right)}\)
\(\displaystyle{ b)}\) \(\displaystyle{ \left(x - 1 \right) \left(x - 2 \right) = \left(x - 3 \right) \left(x - 4 \right)}\)
\(\displaystyle{ c)}\) \(\displaystyle{ 7m + 15 = 3 \left(m +2 \right) + 1}\)
\(\displaystyle{ d)}\) \(\displaystyle{ 3 \left(2x - 1 \right) - 2 \left(4x + 3 \right) = 7 - 4 \left(x + 1 \right)}\)
\(\displaystyle{ b)}\) \(\displaystyle{ \left(x - 1 \right) \left(x - 2 \right) = \left(x - 3 \right) \left(x - 4 \right)}\)
\(\displaystyle{ c)}\) \(\displaystyle{ 7m + 15 = 3 \left(m +2 \right) + 1}\)
\(\displaystyle{ d)}\) \(\displaystyle{ 3 \left(2x - 1 \right) - 2 \left(4x + 3 \right) = 7 - 4 \left(x + 1 \right)}\)