Mieszanina \(\displaystyle{ NaCl}\) i \(\displaystyle{ KCl}\) zawiera \(\displaystyle{ 56,8 \%}\) chloru.
Oblicz procentową zawartość chlorku sodu i chlorku potasu w tej mieszaninie.
mieszanina NaCl i KCl
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pesel
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mieszanina NaCl i KCl
\(\displaystyle{ m=m_{NaCl}+m_{KCl}}\)
\(\displaystyle{ m_{Cl}^{NaCl}={M_{Cl} \cdot \frac{m_{NaCl}}{M_{NaCl}}}\)
\(\displaystyle{ m_{Cl}^{KCl}=M_{Cl} \cdot \frac{m_{KCl}}{M_{KCl}}}\)
\(\displaystyle{ m_{Cl}=m_{Cl}^{NaCl}+m_{Cl}^{KCl}}\)
\(\displaystyle{ \% Cl= \frac{m_{Cl}}{m} \cdot 100 \%=\frac{m_{Cl}^{NaCl}+m_{Cl}^{KCl}}{m} \cdot 100 \%= \frac{M_{Cl} \cdot \frac{m_{NaCl}}{M_{NaCl}}+ M_{Cl}\cdot \frac{m_{KCl}}{M_{KCl}}}{m_{NaCl}+m_{KCl}} \right) \cdot 100 \%= \frac{M_{Cl}}{M_{NaCl}} \cdot \frac{m_{NaCl} \cdot 100 \%}{(m_{NaCl}+m_{KCl})} + \frac{M_{Cl}}{M_{KCl}} \cdot \frac{m_{KCl} \cdot 100 \%}{(m_{NaCl}+m_{KCl})}= \frac{M_{Cl}}{M_{NaCl}} \cdot \%_{NaCl} + \frac{M_{Cl}}{M_{KCl}} \cdot \%_{KCl}= \frac{M_{Cl}}{M_{NaCl}} \cdot \%_{NaCl} + \frac{M_{Cl}}{M_{KCl}} \cdot (100 \%- \%_{NaCl})=56.8 \%}\)
Z tego równania wyznaczamy \(\displaystyle{ \%_{NaCl}}\)
\(\displaystyle{ \%_{KCl}=100 \% -\%_{NaCl}}\)
\(\displaystyle{ m_{Cl}^{NaCl}={M_{Cl} \cdot \frac{m_{NaCl}}{M_{NaCl}}}\)
\(\displaystyle{ m_{Cl}^{KCl}=M_{Cl} \cdot \frac{m_{KCl}}{M_{KCl}}}\)
\(\displaystyle{ m_{Cl}=m_{Cl}^{NaCl}+m_{Cl}^{KCl}}\)
\(\displaystyle{ \% Cl= \frac{m_{Cl}}{m} \cdot 100 \%=\frac{m_{Cl}^{NaCl}+m_{Cl}^{KCl}}{m} \cdot 100 \%= \frac{M_{Cl} \cdot \frac{m_{NaCl}}{M_{NaCl}}+ M_{Cl}\cdot \frac{m_{KCl}}{M_{KCl}}}{m_{NaCl}+m_{KCl}} \right) \cdot 100 \%= \frac{M_{Cl}}{M_{NaCl}} \cdot \frac{m_{NaCl} \cdot 100 \%}{(m_{NaCl}+m_{KCl})} + \frac{M_{Cl}}{M_{KCl}} \cdot \frac{m_{KCl} \cdot 100 \%}{(m_{NaCl}+m_{KCl})}= \frac{M_{Cl}}{M_{NaCl}} \cdot \%_{NaCl} + \frac{M_{Cl}}{M_{KCl}} \cdot \%_{KCl}= \frac{M_{Cl}}{M_{NaCl}} \cdot \%_{NaCl} + \frac{M_{Cl}}{M_{KCl}} \cdot (100 \%- \%_{NaCl})=56.8 \%}\)
Z tego równania wyznaczamy \(\displaystyle{ \%_{NaCl}}\)
\(\displaystyle{ \%_{KCl}=100 \% -\%_{NaCl}}\)