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[arekarekarek]

\(\displaystyle{ \frac{cos \alpha }{sin \alpha - 1}}\) \(\displaystyle{ + tg \alpha = - \frac{1}{cos \alpha }}\)

[mmoonniiaa]

\(\displaystyle{ L= \frac{cosx}{sinx-1} + \frac{sinx}{cosx} = \frac{cos^2x+sinx(sinx-1)}{(sinx-1)cosx} = \frac{cos^2x+sin^2x-sinx}{(sinx-1)cosx} = \frac{1-sinx}{-(1-sinx)cosx} =- \frac{1}{cosx} =P}\)

[arekarekarek]

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