silnia

[hmL]

\(\displaystyle{ \frac{(2n-1)!*(n+2)!}{n!*(2n+2)!}}\)

[sea_of_tears]

\(\displaystyle{ \frac{(2n-1)!\cdot (n+2)!}{n!\cdot (2n+2)!}=
\frac{(2n-1)!\cdot n!(n+1)(n+2)}{n!\cdot (2n-1)!2n(2n+1)(2n+2)}
\newline
=\frac{(n+1)(n+2)}{2n(2n+1)(2n+2)}=
\frac{(n+1)(n+2)}{2n(2n+1)2(n+1)}=
\newline
=\frac{n+2}{4n(2n+1)}}\)

[hmL]

dzięki ;]

[Tomek_Z]

\(\displaystyle{ \frac{(2n-1)!*(n+2)!}{n!*(2n+2)!} = \frac{(2n-1)! (n+2)(n+1)n! }{n! (2n+2)(2n+1)2n(2n-1) } = \frac{(n+2)(n+1)}{2(n+1)(2n+1)2n } = \frac{n+2}{4n(2n+1)}}\)

[hmL]

równiez dzięki ;p