oblicz calke

[gufox]

\(\displaystyle{ \int_{}^{} \frac{xdx}{ \sqrt{x ^{2}-6 } } } = ft\{\begin{array}{l} \sqrt{x ^{2}-6 } =t\\x ^{2}-6=t ^{2} \\2xdx=2t\\xdx= tdt \end{array}= \frac{tdt}{t} =\int_{}^{} dt= t+C= \sqrt{x ^{2} -6} +C}\)

prosze o sprawdzenie.

[Szemek]

\(\displaystyle{ (\sqrt{x^2-6}+C)' = \frac{2x}{2\sqrt{x^2-6}}}\)
jest dobrze