oblicz granice z l`hospitala

[gufox]

\(\displaystyle{ \lim_{ x\to } x(2 ^{ \frac{1}{x} }-2 ^{ -\frac{1}{x} }) =
\lim_{ x\to } \frac{2 ^{ \frac{1}{x}} -2 ^{ -\frac{1}{x} } }{ \frac{1}{x} } =[ \frac{0}{0}]H=}\)

pomoze ktos z tym dalej? dziekuje

[Lorek]

\(\displaystyle{ \lim_{x\to }x(2^\frac{1}{x}-2^{-\frac{1}{x}})=\lim_{t\to 0^+}\frac{2^t-2^{-t}}{t}}\)
i to sobie hospitalizuj.