Jaki procent 1 liczby stanowi 2

[wirus1910]

Jakim procentem liczby
\(\displaystyle{ k= \frac{ \frac{2}{3}- \frac{5}{12} }{ \frac{1}{4}- \frac{3}{16} }}\)jest liczba

\(\displaystyle{ L= \frac{ 3^{2}* 2^{3} }{8*3}}\)?

[maise]

\(\displaystyle{ k= \frac{ \frac{2}{3}- \frac{5}{12} }{ \frac{1}{4}- \frac{3}{16} }\\
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k= \frac{ \frac{8}{12} - \frac{5}{12} }{ \frac{4}{16}- \frac{3}{16} }\\
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k= \frac{ \frac{3}{12} }{ \frac{1}{16} } \\
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k= \frac{3}{12} *16 \\
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k=4\\
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L= \frac{3^2*2^3}{8*3} \\
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L= \frac{9*8}{8*3} \\
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L=3
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4=100 \\
3=x\\
\\
x= \frac{3*100 }{4} \\
x=75 }\)

[coldpeer]

K = 4
L = 3

4 - 3
100% - x
4x = 100% * 3
4x = 300%
x = 300% / 4 = 75%