Oblicz granicę...
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lila
- Użytkownik

- Posty: 13
- Rejestracja: 28 maja 2008, o 14:19
- Płeć: Kobieta
- Lokalizacja: Poznań
- Pomógł: 2 razy
Oblicz granicę...
\(\displaystyle{ \lim_{x\to\infty} ( \frac{4n-2}{4n+6} ) ^{3n} =}\)
\(\displaystyle{ \lim_{x\to\infty} ( \frac{4n+6-8}{4n+6} ) ^{3n} =}\)
\(\displaystyle{ \lim_{x\to\infty} ( 1 +\frac{1}{ \frac{4n+6}{-8} } ) ^{3n} =}\)
\(\displaystyle{ \lim_{x\to\infty} ( 1 +\frac{1}{ \frac{4n+6}{-8} } ) ^{( \frac{4n+6}{-8} ) ( \frac{-8}{4n+6} ) 3n} =}\)
\(\displaystyle{ \lim_{x\to\infty} e^{ \frac{-8 3n}{4n+6} =}\)
\(\displaystyle{ e ^{-6}}\)
\(\displaystyle{ \lim_{x\to\infty} ( \frac{4n+6-8}{4n+6} ) ^{3n} =}\)
\(\displaystyle{ \lim_{x\to\infty} ( 1 +\frac{1}{ \frac{4n+6}{-8} } ) ^{3n} =}\)
\(\displaystyle{ \lim_{x\to\infty} ( 1 +\frac{1}{ \frac{4n+6}{-8} } ) ^{( \frac{4n+6}{-8} ) ( \frac{-8}{4n+6} ) 3n} =}\)
\(\displaystyle{ \lim_{x\to\infty} e^{ \frac{-8 3n}{4n+6} =}\)
\(\displaystyle{ e ^{-6}}\)

