granica ciągu

kasiunia-jo · Post autor: **kasiunia-jo** » 19 lut 2008, o 16:50

\(\displaystyle{ \lim_{n\to } \frac{(-1) ^{n} }{n ^{2}+1 }}\)

dziękuje za pomoc;]

Baca48 · Post autor: **Baca48** » 19 lut 2008, o 17:52

\(\displaystyle{ \lim_{n \to } \frac{(-1) ^{n} }{n ^{2}+1 } = \lim_{n \to } \frac{ \frac {(-1) ^{n}}{n^{2}} }{\frac{n ^{2}}{n^{2}} + \frac {1}{n^{2}} } = \lim_{n \to } \frac{ \frac {(-1) ^{n}}{n^{2}} }{1 + \frac {1}{n^{2}} } = 0}\)