Ułamki.

[darki]

Proszę o pomoc w tym zadaniu.

\(\displaystyle{ 1\frac{3}{4}*(6\frac{2}{9}-5\frac{5}{16})-2^2-\sqrt{\frac{49}{81}}}\)

[soku11]

\(\displaystyle{ \frac{7}{4}\cdot (\frac{56}{9}-\frac{85}{16})-4-\frac{7}{9}=
\frac{7}{4}\cdot (\frac{896}{144}-\frac{765}{144})-\frac{36}{9}-\frac{7}{9}=
\frac{7}{4}\cdot \frac{131}{144}-\frac{43}{9}=
\frac{917}{576}-\frac{2752}{576}=-\frac{1835}{576}}\)

Hmpf... Jakos dziwnie POZDRO

[mostostalek]

\(\displaystyle{ 1\frac{3}{4}*(6\frac{2}{9}-5\frac{5}{16})-2^2-\sqrt{\frac{49}{81}}=\frac{7}{4} (1\frac{32}{144}-\frac{45}{144})-4-\frac{7}{9}=\frac{7}{4} \frac{131}{144}-\frac{7}{9}-4=\frac{917}{576}-\frac{448}{576}-4=\frac{469}{576}-4=-3\frac{107}{576}}\)

taa dziwnie