pochodne

kamat · Post autor: **kamat** » 23 sie 2007, o 15:53

a) \(\displaystyle{ f(x)=\sqrt[]{{a{sin}^2}x + b{cos}^2}x}}\)

b) \(\displaystyle{ f(t) = \frac{{\ 1 - 4 sin x}}{{cos x}}}\)

ariadna · Post autor: **ariadna** » 23 sie 2007, o 15:59

b)
\(\displaystyle{ f^{'}(x)=\frac{-4cosx(cosx)+(1-4sinx)sinx}{cos^{2}x}=\frac{sinx-4}{cos^{2}x}}\)

Kostek · Post autor: **Kostek** » 23 sie 2007, o 16:02

a)
\(\displaystyle{ f'(x)=\frac{(asinxcosx-bsinxcosx)}{\sqrt{asin^{2}x+bcos^{2}x}}}\)
b)
\(\displaystyle{ f'(x)=\frac{sinx}{cos^{2}x}-\frac{4}{cos^{2}x}=\frac{sinx-4}{cos^{2}x}}\)