całki
: 25 lis 2008, o 07:55
Cześć, prosze o pomoc
Olicz całkę;
\(\displaystyle{ \int_{2}^{3}(4-x ^{3})dx}\)
Olicz całkę;
\(\displaystyle{ \int_{2}^{3}(4-x ^{3})dx}\)
\(\displaystyle{ \int_{1}^{2}(4-x^2)dx=
t_{1}^{2}4dx - t_{1}^{2}x^2 dx=
t_{1}^{2}4dx - \frac{1}{3}\int_{1}^{2}3x^2dx=
4x |_{1}^{2} -\frac{1}{3}x^3 |_{1}^{2}=
4\cdot2-4\cdot 1-(\frac{1}{3}\cdot 2^3 - \frac{1}{3}\cdot 1^3)=
8-4 -(\frac{8}{3}-\frac{1}{3})=4-\frac{7}{3}=\frac{12}{3}-\frac{7}{3}=\frac{5}{3}=1\frac{2}{3}}\)