do sprawdzenia granice.
: 25 sty 2011, o 17:14
\(\displaystyle{ \lim_{ x\to \infty } \frac{3}{ \sqrt{4n ^{2}+3n }-2n }=4}\)
\(\displaystyle{ \lim_{x \to \infty } \frac{5n+sin5n}{15n+15}= \frac{1}{3}}\)
\(\displaystyle{ \lim_{ x\to \infty }\left( \frac{n+9}{n+5} \right) ^{3n+2}=e ^{12}}\)
\(\displaystyle{ \lim_{x \to \infty } \frac{5n+sin5n}{15n+15}= \frac{1}{3}}\)
\(\displaystyle{ \lim_{ x\to \infty }\left( \frac{n+9}{n+5} \right) ^{3n+2}=e ^{12}}\)