nierówność z symbolem newtona

[joasia777]

\(\displaystyle{ {19 \choose k-1} < {19 \choose k}}\)

[zati61]

\(\displaystyle{ \frac{19!}{(k-1)!(20-k)!)} < \frac{19!}{k!(19-k)!}\\
(k-1)!= \frac{k!}{k} \quad (19-k)!= \frac{20-k)!}{20-k}}\)