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[mycha-mycha1]

Wiadomo że
\(\displaystyle{ P(A \cup B)=0,95}\)
\(\displaystyle{ P(A \cap B)=0,55}\)
\(\displaystyle{ 3P(a)=2P(B)}\)

oblicz \(\displaystyle{ P(B')}\) i \(\displaystyle{ P(B \backslash A)}\)



obliczyłam \(\displaystyle{ P(B')}\) ale mam problem z \(\displaystyle{ P(B \backslash A)}\)

[Lbubsazob]

\(\displaystyle{ P \left(A \cup B \right)=P(A)+P(B)-P \left(A \cap B \right) \\
3P(A)=2P(B) \rightarrow P(B)= \frac{3}{2}P(A) \\
\\
0,95=P(A)+1,5P(A)-0,55 \\
1,5=2,5P(A) \\
P(A)=0,6 \\
P(B)=0,6\cdot 1,5=0,9 \\
P(B')=1-P(B)=0,1}\)

[mycha-mycha1]

czytaj uważnie


obliczyłam \(\displaystyle{ P(B')}\) ale mam problem z \(\displaystyle{ P(B \backslash A)}\)

[Lbubsazob]

\(\displaystyle{ P \left(B/A \right)=P(B)-P \left(A \cap B \right)\\
P \left(B/A \right)=0,9-0,55=0,35}\)