Dany jest okrąg o równaniu: \(\displaystyle{ (x - 4) ^{2} + (y + 3) ^{2} = 4}\)
\(\displaystyle{ (x - 4) ^{2} + (y + 3) ^{2} = 4}\)
\(\displaystyle{ x ^{2} - 8x + 16 + y ^{2} + 6y + 9 = 0}\)
\(\displaystyle{ 10x ^{2} - 8x + y ^{2} + 6y + 21 = 0}\)
\(\displaystyle{ 10x ^{2} + y ^{2} - 8x + 6y + 21 =0}\)
\(\displaystyle{ 10x ^{2} - 8x + y ^{2} + 6y + 21 = 0}\)
\(\displaystyle{ (5x - 4) ^{2} - 8 + (y + 3) ^{2} - 6 + 21 = 0}\)
\(\displaystyle{ (5x - 4) ^{2} + (y + 3) ^{2} = -1}\)
\(\displaystyle{ S= (4, -3) r= -2}\)
dobrze zadanie jest zrobione?
