równanie

[dziadek.borys]

\(\displaystyle{ cos(2x - \frac{\pi}{6} ) - cos (x + \frac{\pi}{6} ) = 0}\)

[Nakahed90]

\(\displaystyle{ \cos (2x-\frac{\pi}{6})=\cos (x+\frac{\pi}{6})}\)
\(\displaystyle{ 2x-\frac{\pi}{6}=x+\frac{\pi}{6}+2k \pi 2x-\frac{\pi}{6}=-x-\frac{\pi}{6}+2k \pi k\in C}\)
\(\displaystyle{ x=\frac{\pi}{3}+2k \pi x=k\frac{2\pi}{3} k\in C}\)

[dziadek.borys]

a..?
\(\displaystyle{ tg2x=tg(3x- \frac{\pi}{6})}\)

[Nakahed90]

\(\displaystyle{ 2x=3x-\frac{\pi}{6} +k\pi k\in C}\)
\(\displaystyle{ x=\frac{\pi}{6}-k\pi k\in C}\)

[ Dodano: 11 Listopada 2008, 12:27 ]
Zapis
x=frac{pi}{6}-kpi kin C
jest równoważny zapisowi
x=frac{pi}{6}+kpi kin C