Matematyka.pl

specjalnie dla pewnej osóbki, która nie umie się texem posługiwać:

a) \(\displaystyle{ \tan{\frac{3\pi}{4}}\cdot\sin{\frac{7\pi}{6}}+\cot{\frac{5\pi}{4}}\cdot\cos{\frac{4\pi}{3}}=}\)

b) \(\displaystyle{ \sin{\frac{11\pi}{6}}:\cos{\frac{2\pi}{3}}-\tan{\frac{5\pi}{3}}\cot{\frac{5\pi}{6}}=}\)

c)\(\displaystyle{ \cos{(-\frac{\pi}{6})}\cdot\tan{(-\frac{5\pi}{6})}\cdot\sin{(-\frac{\pi}{3})}\cdot\cot{(-\frac{2\pi}{3})}=}\)

d)\(\displaystyle{ \sin{(-\frac{7\pi}{6})}\cdot\cos{(-\frac{5\pi}{4})}+\tan{(-\frac{5\pi}{3})}\cdot\cot{(-\frac{3\pi}{4})}}\)

a)
\(\displaystyle{ tg\frac{3\pi}{4}\cdot \sin\frac{7\pi}{6}+ctg\frac{5\pi}{4}\cdot cos\frac{4\pi}{3}=tg (\pi-\frac{\pi}{4})\cdot sin(\pi +\frac{\pi}{6}+ctg(\pi+ \frac{\pi}{4})\cdot cos(\pi+\frac{\pi}{4})=-tg\frac{\pi}{4}\cdot (-sin \frac{\pi}{6})+ctg\frac{\pi}{4}\cdot (-cos\frac{\pi}{4})=-1\cdot (-\frac{1}{2})+1\cdot \frac{\sqrt{2}}{2}=\frac{1}{2}+\frac{\sqrt{2}}{2}=\frac{1+\sqrt{2}}{2}}\)

Matematyka.pl

zadania - trygonometria..

zadania - trygonometria..

zadania - trygonometria..