wyznacz liczbe x

[maxiking99]

x = \(\displaystyle{ log _{16}sin \frac{3 \pi }{4} + 16 ^{cos \frac{2 \pi }{3} }}\)-- 28 kwi 2010, o 15:56 --

[rodzyn7773]

\(\displaystyle{ x = log _{16}sin \frac{3 \pi }{4} + 16 ^{cos \frac{2 \pi }{3} } = \frac{1}{4} log_2 ( \frac{ \sqrt{2} }{2} )+2^{- \frac{1}{2} *4}= \frac{1}{4} log_2 2^{- \frac{1}{2} }+ \frac{1}{4} =- \frac{1}{8} + \frac{1}{4} = \frac{1}{8}}\)