\(\displaystyle{ \left( x+1\right) \cdot \left( x^{4}-3x^{3}+4x^{2}-3x+3\right) = 0}\)
To już \(\displaystyle{ x+1}\) masz. Teraz dalej. Trzeba troche sztuczek znac.
\(\displaystyle{ x^{4}-3x^{3}+4x^{2}-3x+3 = 0 \\ x^{4}+x^{2}+3x^{2}+3-3x^{3}-3x = 0 \\x^{2}\cdot\left( x^{2}+1\right)+3 \cdot \left( x^{2}+1\right)-3x \cdot \left( x^{2}+1 \right) = 0 \\ \left( x^{2}+1\right) \cdot \left( x^{2}-3x+3\right) = 0}\)