Rozwiąż równania - zdanie wielomiany

[asdas13]

a) \(\displaystyle{ x^{4}-3(x^{2}-1)=7(x^{2}-3)}\)
b) \(\displaystyle{ x^{6}-3x^{3}-40=0}\)

[kajus]

\(\displaystyle{ x^{6}-3x^{3}-40=0\\
t=x^3\\
t^2-3t-40=0\\
\Delta=9+160=169\\
t_{1}=\frac{3-13}{2}=-5\\\\
t_{2}=\frac{3+13}{2}=8\\\\
x^3=8\\
x=2\\
x^3=-5\\
x=\sqrt[3]{-5}}\)