pierwiastek z pierwiastka

zuliaaa · Post autor: **zuliaaa** » 2 mar 2010, o 18:14

ile to jest:
\(\displaystyle{ \sqrt{8 - 4 \sqrt{3}}}\)

Althorion · Post autor: **Althorion** » 2 mar 2010, o 18:17

Ukryta treść:

Po zmienieniu posta:
\(\displaystyle{ \sqrt{8 - 4 \sqrt{3}} = \sqrt{ 4 \left( 2 - \sqrt{3} \right) } = 2 \sqrt{ 2 - \sqrt{3} }}\)

zuliaaa · Post autor: **zuliaaa** » 2 mar 2010, o 18:20

\(\displaystyle{ \sqrt{8-4 \sqrt{3} }}\)-- 2 mar 2010, o 18:28 --\(\displaystyle{ \sqrt{2- \sqrt{3} }* \sqrt{2+ \sqrt{3} }}\)

del1071 · Post autor: **del1071** » 2 mar 2010, o 18:29

\(\displaystyle{ \sqrt{8 - 4 \sqrt{3}}=\sqrt{2-2 \cdot 2 \sqrt{3}+6 }= \sqrt{(\sqrt{2}- \sqrt{6})^2} = | \sqrt{2}- \sqrt{6}|= \sqrt{6}-\sqrt{2}}\)

zuliaaa · Post autor: **zuliaaa** » 2 mar 2010, o 18:39

\(\displaystyle{ \sqrt{8 \sqrt{3} }}\)

zuliaaa · Post autor: **zuliaaa** » 17 mar 2010, o 19:04

\(\displaystyle{ 5^{17}-5^{16}}\) ile to jest?

Althorion · Post autor: **Althorion** » 18 mar 2010, o 06:36

\(\displaystyle{ 5^{17}-5^{16} = 5^{16}(5 - 1) = 4\cdot 5^{16}}\)

zuliaaa · Post autor: **zuliaaa** » 17 kwie 2010, o 21:53

\(\displaystyle{ - \frac{1}{2}+ \frac{3 \sqrt{3} }{2}=cos \alpha}\)