Wielomiany. Sprawdzenie

[dolores91]

\(\displaystyle{ 1. \frac{x-1}{x+1}: \frac{2x-2}{ x^{2}+x }= \frac{x-1}{x+1} \cdot \frac{x ^{2}+x }{2x-2}= \frac{x-1}{x+1} \cdot \frac{(x+1)(x-1)}{2(x-1)}=x-1}\)

[mmoonniiaa]

tutaj widzę błąd, bo \(\displaystyle{ x^2+x \neq (x+1)(x-1)}\), ale \(\displaystyle{ x^2+x=x(x+1)}\)

[dolores91]

\(\displaystyle{ 1. \frac{x-1}{x+1}: \frac{2x-2}{ x^{2}+x }= \frac{x-1}{x+1} \cdot \frac{x ^{2}+x }{2x-2}= \frac{x-1}{x+1} \cdot \frac{x(x+1)}{2(x-1)}= \frac{x}{2}}\)

Teraz dobrze?

[mmoonniiaa]

tak!