Strona 1 z 1

Granica

: 15 sie 2007, o 12:57
autor: lalus_87
Ile wynosi ta granica:
\(\displaystyle{ \mathop {\lim }\limits_{x \to 1} \frac{{(x + 1)^3 }}{{5\left( {x - 1} \right)^2 }}}\)

Granica

: 15 sie 2007, o 13:22
autor: luka52
\(\displaystyle{ \lim_{x \to 1^-} \frac{(x+1)^3}{5 (x-1)^2} = ft[ \frac{8}{0^+} \right] = + \\
\lim_{x \to 1^+} \frac{(x+1)^3}{5 (x-1)^2} = ft[ \frac{8}{0^+} \right] = + }\)