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[viola1411]

\(\displaystyle{ \sqrt[3]{1/8}* \sqrt{32}* \sqrt[4]{4 ^{-0,(3)} }: \sqrt[5]{128}: \sqrt[6]{4 ^{0,(6)} }=}\)

bardzo proszę o pomoc ....

[mmoonniiaa]

\(\displaystyle{ ((2 ^{-1} ) ^{3} ) ^{ \frac{1}{3} } (2 ^{5} ) ^{ \frac{1}{2} } ((2 ^{2} ) ^{ \frac{-1}{3} } ) ^{ \frac{1}{4} } 2 ^{7} ) ^{ \frac{1}{5} } (2 ^{2} ) ^{ \frac{2}{3} } ) ^{ \frac{1}{6} } =2 ^{-1} 2 ^{ \frac{5}{2} } 2 ^{ \frac{-1}{6} } : 2 ^{ \frac{7}{5} } :2 ^{ \frac{2}{9} } = 2 ^{-1+ \frac{15}{6}- \frac{1}{6} }: 2 ^{ \frac{7}{5} } :2 ^{ \frac{2}{9} } =2 ^{ \frac{4}{3} }: 2 ^{ \frac{7}{5} } :2 ^{ \frac{2}{9} } =...}\)