Strona 1 z 1

mieszanina NaCl i KCl

: 14 lip 2014, o 13:12
autor: kaslina
Mieszanina \(\displaystyle{ NaCl}\) i \(\displaystyle{ KCl}\) zawiera \(\displaystyle{ 56,8 \%}\) chloru.
Oblicz procentową zawartość chlorku sodu i chlorku potasu w tej mieszaninie.

mieszanina NaCl i KCl

: 14 lip 2014, o 15:14
autor: pesel
\(\displaystyle{ m=m_{NaCl}+m_{KCl}}\)

\(\displaystyle{ m_{Cl}^{NaCl}={M_{Cl} \cdot \frac{m_{NaCl}}{M_{NaCl}}}\)

\(\displaystyle{ m_{Cl}^{KCl}=M_{Cl} \cdot \frac{m_{KCl}}{M_{KCl}}}\)

\(\displaystyle{ m_{Cl}=m_{Cl}^{NaCl}+m_{Cl}^{KCl}}\)

\(\displaystyle{ \% Cl= \frac{m_{Cl}}{m} \cdot 100 \%=\frac{m_{Cl}^{NaCl}+m_{Cl}^{KCl}}{m} \cdot 100 \%= \frac{M_{Cl} \cdot \frac{m_{NaCl}}{M_{NaCl}}+ M_{Cl}\cdot \frac{m_{KCl}}{M_{KCl}}}{m_{NaCl}+m_{KCl}} \right) \cdot 100 \%= \frac{M_{Cl}}{M_{NaCl}} \cdot \frac{m_{NaCl} \cdot 100 \%}{(m_{NaCl}+m_{KCl})} + \frac{M_{Cl}}{M_{KCl}} \cdot \frac{m_{KCl} \cdot 100 \%}{(m_{NaCl}+m_{KCl})}= \frac{M_{Cl}}{M_{NaCl}} \cdot \%_{NaCl} + \frac{M_{Cl}}{M_{KCl}} \cdot \%_{KCl}= \frac{M_{Cl}}{M_{NaCl}} \cdot \%_{NaCl} + \frac{M_{Cl}}{M_{KCl}} \cdot (100 \%- \%_{NaCl})=56.8 \%}\)

Z tego równania wyznaczamy \(\displaystyle{ \%_{NaCl}}\)

\(\displaystyle{ \%_{KCl}=100 \% -\%_{NaCl}}\)