pochodna
: 26 sie 2007, o 18:37
\(\displaystyle{ z=\frac{\sin }{ }+\frac{ }{\sin }}\)
\(\displaystyle{ z=\frac{\sin^{2} + ^{2}}{\alpha \sin }}\)
\(\displaystyle{ \frac{dz}{d\alpha}=\frac{(2\sin \cos +2 )(\alpha \sin )-(\sin^{2}\alpha +\alpha^{2})(\sin +\alpha \cos )}{\alpha^{2} \sin^{2} }}\)